Hello, guys, and welcome back.
Now let us design some circuits using an old gauge that we have learned about.
So let us take this example.
We have already talked about the switches before, and we know that the basis of all of this design
is switching.
So assume that we have an energy source here connected in series right here and we have a load right
here.
And this load is could be a bulb.
It could be actually a motor.
Anything that we can turn on and off will analyze this circuit.
We know that whenever we see part of the lines or parallel switches, this is an aggregate.
So we can combine this and we can say, OK, this is an aggregate.
Now, do we see any other parallel lines?
Actually, no.
So this is the only organ that we have here.
Now, we can consider these just one line for the moment in order to see what kind of dependencies we
have in this circuit.
We know that this organ is dependent on S3 and S4, meaning this organ need to be giving us a one as
three need to be giving us a one as we need to be giving us a well in order to have an output of one.
Right.
So remember, whenever we see dependency, we are talking about Adgate.
So we know that these three right here are again engaged with the three inputs.
First input is for as for the second input as far as three and the third input is for the output of
the aggregate.
Now bear with me are going to see this visually in a moment.
The last thing that is unusual is that this right here is a closed switch.
Well, I a closed switch can be presented as another gate.
Why?
Because now the normal state of this, which is what we consider a zero right now, the normal state
of the switch is closed.
Whenever the switch is closed, it is conducting power right here and giving us a one.
So the normal state is zero.
While we closed, it is giving us a one at the output, meaning that the input and the output output
the exact opposite of each other, meaning this is another gate.
Now imagine that we energize this and this is now an open switch.
Right?
So this is a state of one.
When this switch is open, it's not it's normal.
The state it is.
It's excited.
The state.
Well, we have a one here and this is open, meaning we are not conducting any more power, so the output
will be zero.
So one here, meaning zero of.
So this is another proof that this is not a game.
Now, how can we combine these three gates together in order to get this same switching case?
No, we need one or gate for these two.
Right.
So we have S1, S2, and the output will go to the end gateway to, you know, what does this Edgard
contain?
It has a three.
This is a three.
Right.
So we have three.
And S1 and S2 connected like this.
Next, we have this Asfour, which is an object.
So the input here will be a not great, as we can see, right?
And is connected to the earthquake and then this whole Adgate is connected to the load right now, let
us compare the functionality if it's working or not, we need either of these switches to be closed.
We need S3 to be closed, and then we will have a line of power right enough for us to have that.
So assume that S1 is closed and this is an OR gate, so the output here is one.
Great.
So we have one at this and input.
Now remember, with the Adgate will give us an output only when all its inputs are one.
So we have guaranteed our first input to be right here next S3.
Well, we said we need to close as three, so we need a one here.
So we have one at a three and one here.
Great.
We need one more one in order to get an output.
Now as for normal, the state is close.
When it's zero, it's closed, right?
So if we put zero here, we're going to get one at the output here, so we have another one here.
So we have one here, one here, one here, meaning the load is conducting.
Now, let's take a case where the north gate is having a wall.
So if we energize this, it's going to be open and, well, the power here should be cut.
So if we put one at the S4 right here, it's going to be zero because this is an object and this zero
will propagate till here.
So we have now a zero at one of the inputs of the and gates.
Well, this means that there will be no conduction of power because it's an and gate and all of this
need to be one.
So the circuit is actually working as expected.
So let me sum it up first.
You analyze what all gates you have and then you analyze all the dependencies that you can see here.
We have as far as three.
And this whole all gate is combined to one line.
Right.
So we have one line to line.
Three lines depended on each other.
So we have a three lined and gate.
Then we check what kind of knots we have.
We have only one Newdegate right here.
So we just put it at the input and then we connect the to the load.